Assuming,
- F1 = frequency of the writing side.
- F2 = frequency of the reading side.
- D = data burst.
Burst duration = D/F1
Data Rec'd, Rx= (D/F1) * F2, assuming simultaneous read for the duration.
Extra storage during FULL condition, Backlog = D-Rx = D(F1-F2)/F1
To accommodate latency or response time in the receiver, T, we need additional T * F1 locations.
Receiver also needs time to read all this backlog, so the idle time between bursts must be long enough. So this minimum time is called mop-up time = backlog/F2 = D * (F1-F2)/(F1.F2)
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